268. Missing Number

 

Given an array nums containing n distinct numbers in the range [0, n], return the only number in the range that is missing from the array.

 

Example 1:

Input: nums = [3,0,1]

Output: 2

Explanation:

n = 3 since there are 3 numbers, so all numbers are in the range [0,3]. 2 is the missing number in the range since it does not appear in nums.

Example 2:

Input: nums = [0,1]

Output: 2

Explanation:

n = 2 since there are 2 numbers, so all numbers are in the range [0,2]. 2 is the missing number in the range since it does not appear in nums.

class Solution {
public int missingNumber(int[] nums) {
Map<Integer,Integer> result = new HashMap<>();
for(int num:nums){
result.put(num,result.getOrDefault(num,0)+1);
}
for(int i = 0;i<nums.length;i++){
int count = result.getOrDefault(i,0);
if(count == 0){
return i;
}
}
int n = result.size();
return n;
}
}

 

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